Understanding Wave Emission in A Level Physics

Disable ads (and more) with a membership for a one time $4.99 payment

Explore wave emissions, frequency, and wavelengths, with a focus on calculating the number of waves emitted from a source. Perfect for A Level Physics students aiming to deepen their understanding!

When tackling topics in A Level Physics, understanding wave properties is crucial—especially wave emission. Let’s kick things off with a classic example to illustrate how waves work. Imagine a light source emitting waves, and you want to find out how many complete waves are produced in a short burst of time. Let’s say we’re given a wavelength of 600 nm and a time span of 0.01 μs. Sounds familiar, right? This kind of calculation is often a staple in exams.

So, how do we find the number of complete waves emitted? Here’s the magic formula that connects the speed of a wave, its frequency, and its wavelength:

[ v = f \cdot \lambda ]

Where ( v ) represents the speed of the wave (and for light in a vacuum, that's about ( 3 \times 10^8 ) m/s), ( f ) stands for frequency and ( \lambda ) is the wavelength. Understanding this relationship is your roadmap to solving our problem.

Let’s break down the process. First, we need to convert the wavelength from nanometers to meters since the standard unit for wavelength in physics is meters. So, 600 nm is equal to ( 600 \times 10^{-9} ) m. Now, we’ve got our wavelength ready for calculations!

Next, we can find the frequency using the formula mentioned earlier:

[ f = \frac{v}{\lambda} = \frac{3 \times 10^8 , \text{m/s}}{600 \times 10^{-9} , \text{m}} ]

Plugging in those numbers will give you the frequency. Once you calculate that, you’ll discover:

[ f = \frac{3 \times 10^8}{600 \times 10^{-9}} = 5 \times 10^{14} , \text{Hz} ]

But we’re not done yet! Now that we’ve got the frequency, we must find out how many complete waves are emitted in 0.01 μs. This is where a little more math is needed. We know that:

  1. 0.01 μs is equal to ( 0.01 \times 10^{-6} ) s, which is a tiny window of time.
  2. By multiplying the frequency by the duration of time, you find the total number of waves emitted.

So, we calculate:

[ \text{Number of waves} = f \times \text{Time} = 5 \times 10^{14} , \text{Hz} \times 0.01 \times 10^{-6} , \text{s} ]

Carrying out that calculation will lead you to find that approximately ( 5 \times 10^6 ) complete waves are emitted in that brief moment.

Isn’t it fascinating how such exquisite mathematics helps us understand the seemingly simple phenomena of light? This interplay of wavelengths, speed, and frequency exemplifies the beauty of physics.

As you soak all that in, consider practicing similar questions to get the hang of these concepts. The more scenarios you tackle, the more comfortable you'll feel as exam day approaches. After all, who doesn’t appreciate a little preparation before tackling the big stuff?

So there you have it—a sneak peek into the world of wave emission calculations! It’s an essential part of A Level Physics, blending math and science in ways that reveal the wonders of our universe!